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3 years ago

11

Write an equation for the function graphed above.

1 answer:

Rus_ich [418]3 years ago

8 0

Where is the graph ??

Please provide the graph so that we can answer your questions ....

You might be interested in

Which equation results from isolating a radical term and squaring both sides of the equation for the equation sqrt(x+6)+sqrt(x)=

tiny-mole [99]

(sqrt(x+6))^2 + (sqrt(x))^2 = 8^2
x+6 + x = 64

6 0

3 years ago

2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

78, 66, ,42,30 whats the missing number in the sequence

goldenfox [79]

Answer:

54

Step-by-step explanation:

30,42,54,66,78

counting by 12

4 0

3 years ago

Read 2 more answers

9*10^7 is how many times as large as 3*10^3 Please help

sesenic [268]

Answer:

30000 times larger.

Step-by-step explanation:

10^7 * 9/10^3*3

Law of exponents cancel some of the tens.

10^4 * 9/3

Cancel out the three.

10^4 *3

Compute

30000 times larger.

4 0

3 years ago

This will take the smartest brainly player<br> Give explanation

ratelena [41]

Answer:

n^6 is the answer

$n^{6} * n^{\frac{1}{4} } = n^{\frac{25}{4} }$

$\frac{1}{\sqrt[4]{n} } * n^{\frac{25}{4} } = \frac{n^{\frac{25}{4} } }{n^{\frac{1}{4} } } = n^{\frac{25}{4} } - n^{\frac{1}{4} } = n^{6}$

Step-by-step explanation:

6 0

3 years ago