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3 years ago

James is older than Benito. Benito is younger than Mariana. Mariana is younger than James. Describe how to

Mathematics

2 answers:

rosijanka [135]3 years ago

8 0

First Statement

James is older than Benito.

→Age of James > Age of Benito--------(1)

Second Statement

Benito is younger than Mariana.

→Age of Mariana > Age of Benito----------(2)

Third Statement

Mariana is younger than James.

→Age of James > Age of Mariana-----------(3)

Equating (1),(2) and (3)

→Age of James(J) > Age of Mariana(M)>Age of Benito(B)

⇒James will be farthest from right side of number line, that is Farthest distance from point 0(Zero), then Second Farthest from point 0" is Mariana, and then Third one will be Benito, nearest from point "0".

igomit [66]3 years ago

6 0

Answer:bay summer homework???????

Step-by-step explanation:

bay?!?!?!!?

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Which matrix below represents 3 X 3 Identity Matrix (LaTeX: I_{3} I 3).

miskamm [114]

Answer:

Step-by-step explanation:

Matrix D represents 3 x 3 identity matrix.

Because all elements of principal diagonal are 1 and others are zero.

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3 years ago

Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

fomenos

Answer:

$\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1$

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is $2a=|4--10|$ .

$\implies 2a=|14|$

$\implies 2a=14$

$\implies a=7$

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is $(\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)$

We need to use the relation $a^2+b^2=c^2$ to find $b^2$ .

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

$c=|6--3|=9$

$\implies 7^2+b^2=9^2$

$\implies b^2=9^2-7^2$

$\implies b^2=81-49$

$\implies b^2=32$

We substitute these values into the standard equation of the hyperbola to obtain:

$\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1$

$\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1$

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3 years ago

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3 years ago

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In a vegetable garden,1/4 of the plants are peppers. of the pepper plants ,1/3 are yellow peppers. what fraction of the plants a

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3 years ago

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Answer:

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