Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6
Answer:
7/20
Step-by-step explanation:
Seventh grade: Total = 3 + 7 = 10
Number of boys = 7 boys
Probability of a boy being picked = 7/10
Eighth grade: Total 5 + 5 = 10
Number of boys = 5
Probability 5/10 = 1/2
The probability of the correct outcome = 7/10 * 1/2 = 7 / 20
Answer: 7 / 20
Answer:
wheres ur calc
Step-by-step explanation:
9.25 - 0.5 + 0.375 = 9.126
The answer is D hope this helps
That would be tan
(1-cos)(1+cos)=1-cos² which equals to sin²
√sin²/cos²= sin/cos which equals to tan