92-59= hurry i need the answer

Mathematics

2 answers:

eduard2 years ago

7 0

Thirty-three is the answer

MA_775_DIABLO [31]2 years ago

7 0

The answer to the answer you are looking for is 33 :)

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Can you help me please (get brainliest)

marta [7]

9514 1404 393

Answer:

4/25

Step-by-step explanation:

Put the numbers where the letters are and do the arithmetic.

$\left(2\cdot\dfrac{-1}{2}\cdot\dfrac{2}{5}\right)^2=\left(\dfrac{-2}{5}\right)^2=\dfrac{(-2)^2}{5^2}=\boxed{\dfrac{4}{25}}$

6 0

2 years ago

Write an equation in standard form of the hyperbola described.

marishachu [46]

Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

$\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}$