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3 years ago

Solve the equation 5(4+t) = 5t + 20

Mathematics

2 answers:

andrew11 [14]3 years ago

8 0

The answer is T=0 or 0
=
0

shtirl [24]3 years ago

4 0

Answer:

it is infinite solutions

Step-by-step explanation:

because 20+5t=20+5t even if you put any number as the variable

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Please help #22 please sos

iragen [17]

1/5( 5/2 x 4/7 -11/7) + 3/28

Multiply the terms (5/2 x 4/7) in bracket then subtract it from 11/14. Result will be 10/7.

Then multiply 1/5 with 10/7. The result will be 2/7.

2/7 + 3/28 = 11/28

T

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3 years ago

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What attribute do a rectangle, parallelogram, rhombus, and square ALL have in common?

Vikki [24]

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3 years ago

Buster is a puppy who loves playing inside cardboard boxes. Buster's favorite box is shaped like a big cube and is thirty inches

Finger [1]

Answer:

27000 inches^3

Step-by-step explanation:

The volume of a cube is sidelength^3.

The side length is 30 inches, so the volume is 30^3 = 27000 inches^3.

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3 years ago

List the angles of the triangle in order from largest to smallest.

alina1380 [7]

Answer: A, C, B

Step-by-step explanation:

Because "a" has 8 across

And "c" has 10 across

and "b" has 13 across

7 0

3 years ago

F(x)

mina [271]

a) Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

b) The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if $\lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x)$ . This criterion is commonly used to prove continuity of functions.

Rational functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following lateral limits:

$\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty$

$\lim_{x \to -1^{+}} \frac{x}{x^{2}+x} = + \infty$

Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

In addition, we can simplify the function by algebra properties:

$\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}$

$g(x) = \frac{1}{x + 1}$

The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

To learn more on lateral limits: brainly.com/question/21783151

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2 years ago