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4 years ago

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3. Jessica is measuring two line segments. The first line segment is 30 cm long. The second line segment is 500 mm long. How lon

g are the two line segments together? (answer in cm). Remember to show your work to receive full credit.

1 answer:

serious [3.7K]4 years ago

5 0

There are 10 millimeters in one centimeter (centi means 10). 500 millimeters to centimeters (divide by ten) would be 50 centimeters. 50 centimeters added to 30 centimeters is 80 centimeters total.

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If you put 25ml of concentrate in a glass how much water should be added

snow_tiger [21]

Answer:

50 ml of water should be added in the glass.

Step-by-step explanation:

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3 years ago

I keep on getting the wrong answer

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2 years ago

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Give triangle ABC is a right triangle, and angle A is the right angle. If sin(B)=3/5, find the cos(B).

hichkok12 [17]

Answer:

Cos B = 4/5

Step-by-step explanation:

From the question given above, the following data were obtained:

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Cos B =?

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3 years ago

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Answer:

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3 years ago

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Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

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Step-by-step explanation:

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Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

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$C = 2$

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$y(t) = y_{n}(t) + y_{p}(t)$

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b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

4 years ago