Answer:
B) -|x + 3| = 3
D) |x + 3| + 6 = 3
Step-by-step explanation:
A) |x + 3| = 3
B) -|x + 3| = 3
Divide by -1
|x + 3| = -3
Absolute values are 0 or positive so this cannot have a solution
C) |x + 3| + 3 = 3
Subtract 3 from each side
|x + 3| + 3-3 = 3-3
|x + 3| = 0
D) |x + 3| + 6 = 3
Subtract 6 from each side
|x + 3| = -3
Absolute values are 0 or positive so this cannot have a solution
You can simplify it by adding 1 to both sides to get 4x < 12, then divide both sides by 4 to get x < 3.
I hope that answers your question!
x/4 > 2
Simplify by multiplying 4 on both sides
x>8
Which is,
<h2><u><em>
THE SECOND OPTION</em></u></h2>
<u><em></em></u>
<u><em>-Hunter</em></u>
The amount owed increases by $85 in two weeks.
<span>If the loan were "rolled over" at that point at the same interest rate, and this were done for a full year, the total amount owed would be </span>
<span>(1285/1200)^26 * $1200 </span>
<span>If we subtract the original principle, $1200, and calculate the rest (the compounding interest) as a percentage of that principle, we get </span>
<span>[(1285/1200)^26 * $1200 - $1200] / $1200 = 493%</span>
<span><span>1.
</span>The music hall has 20 boxes :
=> on thurs 2/5 were occupied
=> on friday 2/4 were occupied
=> and on saturday 8/10 were occupied.
Let’s find out which day has the most occupied space of the music hall.
2/5 + 2/4 + 8/10 = 6/20 + 7/20 + 10/20
Thurs 2/5 were occupied
=> 6/20 = 0.3
=> 20 * 0.3 = 6 boxes
Friday 2/4 were occupied
=> 7/20 = 0.35
=> 20 * 0.35 = 7 boxes
Saturday 8/10 were occupied.
=> 10/20 = 0.5
=> 20 * .5 = 10 boxes
Thus, during Saturday has the most number of occupied boxes.</span>
