Answer:
Step-by-step explanation:
AD = BD (CD bisects AB means that it divides the line into two equal parts)
So,
AD = BD = AB/2
So,
AD = 3/2
AD = 1.5
<u><em>Now, Finding AC using Pythagorean Theorem:</em></u>
Where c is hypotenuse (AC), a is base (AD) and b is perpendicular (CD)
Taking sqrt on both sides
We know that , in a circle radius perpendicular to chord will bisect the chord.
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Answer:
y = -3/1x + 2
Step-by-step explanation:
1. Find the slope
The points I will use are (-1,5) and (0,2), where x1 = -1, y1 = 5, x2 =0, and y2 =2.
y2-y1/x2-x1
2-5/0-(-1) = -3/1
2. Find the y-intercepy
y = mx + b
You can use any x or y point. I'll use (-1,5)
m= slope, which is -3/1
5= -3/1(-1) +b
5= 3 + b
Subtract 3 from 5 and 3 to get 2=b.
3. Rewrite in slope-intercept form
y = -3/1x + 2
Answer:
2
Step-by-step explanation:
2
Answer:
Step-by-step explanation:
Your question doesn't match the picture. OCR is often inaccurate!—not that it matters much in this case. None of the choices is correct.
(20-4)·6² + 2 + 18 = 16·6² + 2 + 18
= 16·36 + 2 + 18
= 576 + 2 + 18
= 578 + 18
= 596
