Plz help me

Mathematics

2 answers:

defon3 years ago

7 0

Answer:

Step-by-step explanation:

The rate of change in the line of best fit is -34.85 which represents the decrease in the number of available apartments per week since the complex opened.The y-intercept is 938 which represents the number of available apartments when the complex first opened.

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vivado [14]3 years ago

4 0

The rate of change in the line of best fit is -34.85 which represents the decrease in the number of available apartments per week since the complex opened.

The y-intercept is 938 which represents the number of apartments when the complex first opened.

Note: the rate of change is the slope and the y-intercept is the b in the y=mx+b formula.

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ycow [4]

Answer:

z = 1/4

Step-by-step explanation:

See attached image

4 0

3 years ago

Read 2 more answers

Please help whit all of them I can’t fail math it’s the only subject I’m failing in my mama would whoop me please

scoray [572]

I dunno I rlly don't know like seriously I'm in 7th

6 0

3 years ago

A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro

Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let $\mu$ be the true mean weight per apple the company ship. We want to test the next hypothesis

$H_{0}:\mu=120$ vs $H_{1}:\mu\neq 120$ (two-tailed test).

Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

$Z=\frac{\bar{X}-120}{\sigma/\sqrt{n}}$ which is normally distributed. The observed value is

$z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583$ . The rejection region for $\alpha = 0.05$ is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.