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torisob [31]
3 years ago
8

There are 98 balls in a box. 25 of them are red, 19 of them are green, 30 of them are purple,and 24 of them are blue. Suppose Ha

o draws 22 balls from the box with replacement (hedraws the ball, records its color, and then puts it back into the box). Find the probabilitythat he draws 2 red balls, 5 green balls, 10 purple balls, and 5 blue balls.

Mathematics
2 answers:
dlinn [17]3 years ago
6 0

Answer:

Since the balls are drawn with replacement, it means the individual probability  remain constant,

I have solved this problem on paper (Figures Attached).

Thanks.

Nady [450]3 years ago
5 0

Answer:

Since this problem related to the replacement problem thus

Pr(2 red)=(25/98)(25/98)=0.0651

Pr(5 green)=(19/98)(19/98)(19/98)(19/98)(19/98)

Pr(5 green)=2.73*10^-4

Pr(10 purple)=((30/98))^10=7.22*10^-6

Pr(5 blue)=((24/98))^5=8.8*10^-4

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