<span>B=89 lbs ANSWER: The mix contained 89 pounds of Type B coffee.
CHECK:
167lbs-89lbs=78 lbs She used 78 pounds of Type A coffee.
$4.35A+$5.70B=$846.60
$4.35(78)+$5.70(89)=$846.60
$339.30+$507.30=$846.60
$846.60=$846.60</span>
Answer:
(0,-5), I believe.
Step-by-step explanation:
It would equal 15. To get 15, you would first do 1*10= which equals 10. After that, you would add 5 to the 10 then there's your answer. I hoped this helped!
Question:
Factor 
(8 - x)(8 - x)
(8 + x) (8 - x)
(X + 8)(x-8)
Answer:
Option B: 
is the factor
Explanation:
Given that the expression is
We need to find the factor of the given expression.
Let us rewrite the expression as 
Since the expression is of the form 
, let us use the identity 
where a = 8 and b = x
Substituting the values in the identity, then the expression can be written as
Thus, the factor of the expression is
Hence, Option B is the correct answer.
Answer and Step-by-step explanation:
(a) Given that x and y is even, we want to prove that xy is also even.
For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.
(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:
Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.
(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.
