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3 years ago

Somebody help on number 7 please. Thanks

Mathematics

1 answer:

Tatiana [17]3 years ago

8 0

42. because. 12
+30
=42

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Find the third side in simplest radical form:<br> 25

Gre4nikov [31]

Answer:

<h3> $\boxed{ \bold{24}}$ </h3>

Step-by-step explanation:

$\mathsf{given}$

$\mathsf{hypotenuse(h) = 25}$

$\sf{perpendicular (p) = 7}$

$\sf{base(b) = }$ ?

Now, Using Pythagoras theorem

$\sf{{h}^{2} = {p}^{2} + {b}^{2} }$

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Squaring on both sides

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Hope I helped!

Best regards!

8 0

3 years ago

In the expression 2a + 5 + a -14 + 3b which ones are the constants

Finger [1]

Answer:

Step-by-step explanation:

Constant= # without variable

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2 years ago

Read 2 more answers

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

2 years ago