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Digiron [165]
3 years ago
11

What values would make a ploynimal equal to zero if the factors are (x+3) and (x+12)

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0
\bf (x+3)(x+12) =0
\\ \quad \\

\begin{cases}
(x+3)=\cfrac{0}{(x+12)}\to x+3=0\to &x=-3
\\ \quad \\
(x+12)=\cfrac{0}{(x+3)}\to x+12=0\to &x=-12
\end{cases}
Anna71 [15]3 years ago
7 0
The values 35 and 25 would make the answer to this 0
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