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postnew [5]
3 years ago
15

HELP PICTURE IS SHOWN

Mathematics
1 answer:
poizon [28]3 years ago
3 0
Iis the a i think but im not secure
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Which best describes the strength of a model with an r-value of 0.29
olchik [2.2K]
The <u>correct answer</u> is:

It is not a very strong fit.

Explanation:

The r-value, or correlation coefficient, tells us how closely our model fits the data.

The r-values range from -1 to 1.  -1 is a perfect fit of a decreasing model; 1 is a perfect fit of an increasing model.  0 is no fit at all.

Since our r-value is 0.29, this is much closer to 0 than it is to 1 or -1; this means it is not a very strong fit.
5 0
3 years ago
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I need help with this its confusing me too much
Ann [662]
Answer:

Step-by-step explanation:

Join A and C and B and D. And add numbers to the angles formed on one of the diagonal
In triangles ABC and ADC,
Angle 1 = Angle 4
Angle 3 = Angle 2
AC = AC
Therefore, triangle ABC=ADC
Since, ABC=ADC
Similarly, triangle ABD= triangle CDB
Therefore, AB=CD and BC=DA
7 0
2 years ago
I know the answers to this problem. I will give brainiest to the first one who ANSWER IS CORRECT.
const2013 [10]

Answer:

24240300

Step-by-step explanation:

multiply the numbers thand divide by 2.

3 0
2 years ago
What is the definition of a infinitely many solution equation
masya89 [10]

Answer:

Normally infinity means something that never ends, something that has no end, it goes on forever.

Step-by-step explanation:

I don’t actually know if this is right, but in math infinitely means something that goes on forever.

4 0
3 years ago
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The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
3 years ago
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