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Leya [2.2K]
3 years ago
11

You drive 240 miles and use 8 gallons of gasoline. what was your car’s gas mileage? (In miles per gallon)

Mathematics
2 answers:
anastassius [24]3 years ago
6 0

Hi!

<h3>You use 240 miles per 8 gallons. </h3>

240/8

<h3>Simplify</h3>

30/1

<u>30</u>

<h2>You car's gas mileage is 30 miles per gallon. </h2>

Hope this helps! :)

-Peredhel

ch4aika [34]3 years ago
3 0

You use 8 gallons of gasoline to drive 240 miles

To solve, divide 240 with 8

240/8 = 30/1

Your car's mileage is 30 miles per gallon

hope this helps

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What is the answer to 2(9+7)
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Answer: 32

Step-by-step explanation:

1.) Write the initial equation: 2(9+7)

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3.) Multiply the value in the parentheses by 2: 2(16) = 32

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The figure is made up of a cone and a cylinder.

Diameter = 16 ft
radius = 16÷2 = 8ft

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Volume of the cone = \frac{1}{3}  \pi  r^{2} h
Volume of the cone =  \frac{1}{3} \pi 8^{2}(6) = 402.12

Volume of the cyclinder = bh
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3 years ago
Summer day camp is about to begin. Today there are 132 boys signed up and 219 total children signed up. How many more than girls
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Use the divergence theorem to find the outward flux of the vector field F(x,y,z)=2x2i+5y2j+3z2k across the boundary of the recta
aksik [14]

Answer:

The answer is "120".

Step-by-step explanation:

Given values:

F(x,y,z)=2x^2i+5y^2j+3z^2k \\

differentiate the above value:

div F =2 \frac{x^2i}{\partial x}+5 \frac{y^2j}{\partial y}+3 \frac{z^2k }{\partial z}  \\

        = 4x+10y+6z

\ flu \ of \ x = \int  \int div F dx

              = \int\limits^1_0 \int\limits^3_0 \int\limits^1_0 {(4x+10y+6z)} \, dx \, dy \, dz \\\\ = \int\limits^1_0 \int\limits^3_0 {(4xz+10yz+6z^2)}^{1}_{0} \, dx \, dy  \\\\ = \int\limits^1_0 \int\limits^3_0 {(4x+10y+6)} \, dx \, dy  \\\\ = \int\limits^1_0  {(4xy+10y^2+6y)}^3_{0} \, dx   \\\\ = \int\limits^1_0  {(12x+90+18)}\, dx   \\\\= {(12x^2+90x+18x)}^{1}_{0}   \\\\= {(12+90+18)}   \\\\=30+90\\\\= 120

6 0
3 years ago
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