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2 years ago

You drive 240 miles and use 8 gallons of gasoline. what was your car’s gas mileage? (In miles per gallon)

Mathematics

2 answers:

anastassius [24]2 years ago

6 0

Hi!

<h3>You use 240 miles per 8 gallons. </h3>

240/8

<h3>Simplify</h3>

30/1

<h2>You car's gas mileage is 30 miles per gallon. </h2>

Hope this helps! :)

-Peredhel

ch4aika [34]2 years ago

3 0

You use 8 gallons of gasoline to drive 240 miles

To solve, divide 240 with 8

240/8 = 30/1

Your car's mileage is 30 miles per gallon

hope this helps

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-4(-6 - 2n) = 30 + 8n

kati45 [8]

Answer:

n=6/4

Step-by-step explanation:

-4(-6-2n)=30+8n

24+12n=30+8n

-24 =-24

12n=6+8n

-8n = -8n

4n=6

n=6/4

8 0

2 years ago

Steve sells half of his comic books and then buys 6 more now he has 14 comic books

ddd [48]

Let b be the initial amount of books. Steve sells half of his books, so the number of Steve's books become

$b \to \dfrac{b}{2}$

Then, he buys 6 more, so the number increases by 6:

$\dfrac{b}{2} \to \dfrac{b}{2}+6$

This number is now 14, so you have

$\dfrac{b}{2}+6 = 14$

Subtract 6 from both sides:

$\dfrac{b}{2} = 8$

Multiply both sides by 2:

$b = 16$

4 0

2 years ago

Read 2 more answers

(14x-5)-(-3x+2)<br><br>A. 11x-3<br>B. 17x-7<br>C. 17x-3<br>D. 11x-7

Vladimir [108]

The answer would be B) 17x-7

4 0

2 years ago

15. find the values of x and y

zloy xaker [14]

Answer:

y = 8

x = 21

Step-by-step explanation:

Find x first. Since there is a straight line, we can conclude it's equal to 180 degrees.

11x + 10 -61 = 180

Add 10 to negative 61.

11x - 51 = 180

Add 51 to both sides.

11x = 231

Divide 11 both sides

x = 21.

Now put x in the equations to solve.

This is for the small angle on the right side.

(21+10) = 31

This is for the big angle on the right side.

(10(21) - 61)

210 - 61 = 149.

Now for the other side, we know the degree for the smaller side on the left side since it's a vertical angle.

31 degrees for top left angle. Since we know this side is 180 just subtract 31 from 180 and you'll get 149.

18y + 5 = 149

Subtract 5 both sides.

18y = 144

y = 8.

3 0

2 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi

stealth61 [152]

Applying our power rule gets us our first derivative,

$\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}$

simplifying a little bit,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

looking for critical points,

$\rm 0=2x^{-2/3}+4x^{1/3}$

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

$0=2x^{-2/3}\left(1+2x\right)$

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

$\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)$

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

and take our second derivative.

$\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Looking for inflection points,

$\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Again, pulling out the smaller power of x, and fractional part,

$\rm 0=-\frac43x^{-5/3}\left(1-x\right)$

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.

8 0

3 years ago