Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.
<h3>How do we verify if a sequence converges of diverges?</h3>
Suppose an infinity sequence defined by:
Then we have to calculate the following limit:
If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.
In this problem, the function that defines the sequence is:
Hence the limit is:
Hence, the infinite sequence converges, as the limit does not go to infinity.
More can be learned about convergent sequences at brainly.com/question/6635869
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Answer:
Let's see what to do buddy....
Step-by-step explanation:
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FG = FH + HG ----¢ FG = 14 + 6 = 20
FG = 20
And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
Answer:
a:) Integer Sequences
b:) 1, 3, 6, 10, 15, 21, 28, 36, 45, 55, 66, 78, 91, 105, 120, 136, 153, 171, 190, 210, ...
Step-by-step explanation:
Answer:
16.00
Step-by-step explanation:
19.99 - 25% + 6% = 15.89 =16.00
Answer:
The minimum cost is $9,105
Step-by-step explanation:
<em>To find the minimum cost differentiate the equation of the cost and equate the answer by 0 to find the value of x which gives the minimum cost, then substitute the value of x in the equation of the cost to find it</em>
∵ C(x) = 0.5x² - 130x + 17,555
- Differentiate it with respect to x
∴ C'(x) = (0.5)(2)x - 130(1) + 0
∴ C'(x) = x - 130
Equate C' by 0 to find x
∵ x - 130 = 0
- Add 130 to both sides
∴ x = 130
∴ The minimum cost is at x = 130
Substitute the value of x in C(x) to find the minimum unit cost
∵ C(130) = 0.5(130)² - 130(130) + 17,555
∴ C(130) = 9,105
∵ C(130) is the minimum cost
∴ The minimum cost is $9,105
