Geometry help 10 points

Mathematics

2 answers:

Arlecino [84]3 years ago

7 0

Your Answer Is: A. I Hoped This Helped! Good Luck On Your Studies!

Serhud [2]3 years ago

3 0

The answer to the reflection question would be D.

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Simplify this expresion.<br><br> (6x^5/2x^2)^2

Gwar [14]

Answer:

9x^14

Step-by-step explanation:

PEMDAS

do whats in the parenthesis then do the ^2

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3 years ago

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Determine all values of k for which the roots of the equation x^2-6x+k=0 are complex

MaRussiya [10]

Complex roots occur when b^2 - 4ac is negative.

So we have (-6)^2 - 4.1.k < 0
-4k < - 36
k > 9

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3 years ago

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bija089 [108]

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Growth Models 19515. In 1968, the U.S. minimum wage was $1.60 per hour. In 1976, the minimum wagewas $2.30 per hour. Assume the

VikaD [51]

In general, the exponential growth function is given by the formula below

$f(x)=a(1+r)^x$

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

$\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}$

And 1976 is n=16

$\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}$

Solve the two equations simultaneously, as shown below

$\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}$

Solving for a,