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3 years ago

Determine all values of k for which the roots of the equation x^2-6x+k=0 are complex

Mathematics

1 answer:

MaRussiya [10]3 years ago

6 0

Complex roots occur when b^2 - 4ac is negative.

So we have (-6)^2 - 4.1.k < 0
-4k < - 36
k > 9

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Steven has a counter that is yellow on one side and blue on the other. The counter is shown below:

mihalych1998 [28]

In this situation, it is similar to a coin flip, so think about flipping a 2 sided chip, one side colored yellow the other blue, flipping the chip will result in a 50/50 chance for it to land on either side, so no matter how many times you flip it it will always be a 1/2 chance of it being on one of the sides

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3 years ago

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Using the discriminant, how many real number solutions does this equation have? 3x^2 – 2 = 5x

Anvisha [2.4K]

The discriminant of this equation is 49. The solutions for this equation are x=2 and x=- $\frac{1}{3}$
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2 years ago

Louis bought a burger and soda for $8. Kate purchased a slice of pizza and soda for $9. Biff purchased a burger, a slice of pizz

Arte-miy333 [17]

The equation for Louis's purchase is: $x+y=8$

The equation for Kate's purchase is: $y+z=9$

The equation for Biff's purchase is: $x+y+z=13.50$

Step-by-step explanation:

First of all we have to define variables for each item involved in the purchase

Let x represent burger

y represent soda

z be the slice of pizza

Then

"Louis bought a burger and soda for $8"

$x+y=8$

"Kate purchased a slice of pizza and soda for $9"

$y+z=9$

"Biff purchased a burger, a slice of pizza and a soda for $13.50"

$x+y+z=13.50$

The equation for Louis's purchase is: $x+y=8$

The equation for Kate's purchase is: $y+z=9$

The equation for Biff's purchase is: $x+y+z=13.50$

Keywords: Linear Equations, Variables

Learn more about Linear equations at:

#LearnwithBrainly

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3 years ago

Give another name for line b

k0ka [10]

Answer:

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i don't know

Step-by-step explanation:

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2 years ago

PLZ HELP WILL GIVE BRAINLIEST WORTH 10 PTS THX!!

antiseptic1488 [7]

Answer:

64/49

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)^c = a^(bc)

(a^b)(a^c) = a^(b+c)

a^-b = 1/a^b

a^0 = 1

_____

Using these rules, we can simplify the given expression to ...

$\left(\dfrac{8\cdot 4\cdot 2}{8\cdot 7}\right)^2\times\left(\dfrac{8^0}{7^{-3}}\right)^3\times 7^{-9}\\\\=\dfrac{8^2}{7^2}\times(8^{0\cdot 3}\cdot 7^{3\cdot 3})\times 7^{-9}\\\\=\dfrac{64}{49}\times(8^07^{9-9})=\boxed{\dfrac{64}{49}}$

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3 years ago

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