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Flura [38]
3 years ago
12

Is 1.31 greater then 1.2?

Mathematics
2 answers:
Basile [38]3 years ago
7 0

Yes, 1.31 is 0.11 greater than 1.2.

BigorU [14]3 years ago
4 0

Answer:

Yes because 1.31 and 1.2. 3 is more than 2

Step-by-step explanation:


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A ball is thrown into the air. The height in feet of the ball can be modeled by the equation h = -16t2 + 20t + 6 where t is the
makkiz [27]

f(t)=h=-16t^2+20t+6



a=-16, b=20, c =6

Δ=b^2-4ac=20^2-4*(-16)*6=400+384=784

\sqrt{Δ}=\sqrt{784}=28

max:

p=-\frac{b}{2a}=-\frac{20}{-32}=\frac{20}{32}=\frac{5}{8}

max heigh: h=-16(\frac{5}{8})^2+20*\frac{5}{8}+6=-16\frac{25}{64}+\frac{100}{8}+6

h=-\frac{25}{4}+\frac{50}{4}+6=\frac{-25+50+24}{4}=\frac{49}{4}

h=\frac{49}{4} at t=\frac{5}{8}s


will fall down at t:

t=\frac{-20-28}{-32}=\frac{-48}{-32}=\frac{3}{2}=1.5

t=1.5s

8 0
3 years ago
Evaluate the expression,<br> if x = 9, y = 14, and z = 6.<br> x• y - z^2
alex41 [277]
The answer is 90. Hope this helps
7 0
2 years ago
Read 2 more answers
The brand manager for a brand toothpaste must plan a campaign designed to increase brand recognition. He wants to first determin
bulgar [2K]

We need to find out how many adults must the brand manager survey in order to be 90% confident that his estimate is within five percentage points of the true population percentage.

From the given data we know that our confidence level is 90%. From Standard Normal Table we know that the critical level at 90% confidence level is 1.645. In other words, Z_{Critical}=1.645.

We also know that E=5% or E=0.05

Also, since, \hat{p} is not given, we will assume that \hat{p}=0.5. This is because, the formula that we use will have \hat{p}(1-\hat{p}) in the expression and that will be maximum only when \hat{p}=0.5. (For any other value of \hat{p}, we will get a value less than 0.25. For example if, \hat{p} is 0.4, then 1-\hat{p}=0.6 and thus, \hat{p}(1-\hat{p})=0.24.).

We will now use the formula

n=(\frac{Z_{Critical}}{E})^2\hat{p}(1-\hat{p})

We will now substitute all the data that we have and we will get

n=(\frac{1.645}{0.05})^2\times0.5(1-0.5)

n=(32.9)^2\times0.25

n=270.6025

which can approximated to n=271.

So, the brand manager needs a sample size of 271

3 0
3 years ago
Solve for g. C = d/g
icang [17]

Answer:

I believe that g=dc

Step-by-step explanation:

You swap positions with g and c along with their sign of operation.

7 0
3 years ago
How can i determine if the linear relationship between the variables x and y is proportional?
babymother [125]
If it goes through the origin of a graph
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