Question

In triangle xyz, z2 = x2 + y2. triangle xyz has sides x, qy, z opposite to the corresponding vertices x, y, z which equation is true about the measure of the angles of the triangle? the measure of angle xyz is equal to 100 degrees the measure of angle xzy is equal to 90 degrees the measure of angle xyz plus the measure of angle yxz is equal to 80 degrees the measure of angle xyz plus the measure of angle yxz is equal to 70 degrees

Answer 1

${\text{In triangle XYZ}},{\text{ square of one side is equal to the sum of squares of other two sides, }} \hfill \\ {\text{,i}}{\text{.e}}{\text{., if triangle XYZ has sides of measure }}x\,{\text{unit, }}y\,{\text{unit and }}z\,{\text{unit}} \hfill \\ {\text{opposite to the corresponding vertices }}X,{\text{ }}Y\,{\text{and }}Z\,{\text{respectively, then}} \hfill \\ {z^2} = {x^2} + {y^2} \hfill \\ {\text{Since, the given triangle satisfying the condition of Pythagoras theorem, }} \hfill \\{\text{thus, the given triangle would be a right angled triangle and thereby the measure}} \hfill \\{\text{of one angle of triangle will be a right angle say at vertex Z}}{\text{.}} \hfill \\\Rightarrow m\left( {\angle Z} \right) = 90^\circ \hfill \\\Rightarrow m\left( {\angle XZY} \right) = 90^\circ \hfill \\{\text{Thus,the measure of angle XZY is equal to }}90{\text{ }}degrees. \hfill$

Answer 2

Answer:

Measurement of XZY=90 degrees!

Step-by-step explanation:

I got it correct on my test :)