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GaryK [48]
4 years ago
13

Will give brainliest! Which are simplified forms of the expression sec^2theta sin2theta

Mathematics
1 answer:
Ronch [10]4 years ago
8 0
\bf \cfrac{sin(2\theta )}{cos^2(\theta )}\implies \cfrac{1}{cos^2(\theta )}\cdot sin(2\theta )\implies sec^2(\theta )sin(2\theta )\\\\
-------------------------------\\\\
2tan(\theta )\implies \cfrac{2sin(\theta )}{cos(\theta )}\implies \cfrac{2sin(\theta )cos(\theta )}{cos(\theta )cos(\theta )}\implies \cfrac{2sin(2\theta )}{cos^2(\theta )}
\\\\\\
\cfrac{1}{cos^2(\theta )}\cdot sin(2\theta )\implies sec^2(\theta )sin(2\theta )
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Answer:

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Step-by-step explanation:

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Answer:

Fraction of the figure shaded = \frac{13}{16}

Step-by-step explanation:

Ratio of the areas of the given circles are 1 : 4 : 16

Then the radii of the circles will be in the ratio = \sqrt{1}:\sqrt{4}:\sqrt{16}

                                                                             = 1 : 2 : 4

If the radius of the smallest circle = x units

Then the radius of the middle circle = 2x units

and the radius of the largest circle = 4x units

Area of the smallest circle = πx²

Area of the middle circle = π(2x)² = 4πx²

Area of the largest circle = π(4x)²= 16πx²

Area of the region which is not shaded in the middle circle = πx²(4 - 1)

                                                                                                  = 3πx²

Therefore, area of the shaded region = Area of the largest circle - Area of the region which is not shaded

= 16πx² - 3πx²

= 13πx²

Fraction of the figure which is not shaded = \frac{\text{Area of the shaded region}}{\text{Area of the largest circle}}

= \frac{13\pi x^{2} }{16\pi x^{2} }

= \frac{13}{16}

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Answer:

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245 to the nearest 10?
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