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4 years ago

What is the value of x?

Mathematics

1 answer:

Elina [12.6K]4 years ago

4 0

Answer: 70

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Find the zeros of the function f(x) = 1/3 x^2 + 72

Alexus [3.1K]

To find the zeros of an equation equate the equation to zero

Please with this question I don’t really get it looking at how u hv written it
Is the x^2 a numerator or a denominator
I don’t really get how u wrote ur question

6 0

3 years ago

Aşağıda verilen balik kılçığı diyagramını tamamlayalım.<br>

oee [108]

Answer:

Let's complete the fishbone diagram given below

thats what they said

Step-by-step explanation:

8 0

3 years ago

A group of rectangular prisms is shown.

scoray [572]

Answer:

D, E and F

calculating the volume of regular bodies like prims works by multiplication alone.

you need some addition for surface area and for more complicated bodies that when the volume can't be calculated in one step

8 0

3 years ago

You must get a 90 or higher to pass the course

pentagon [3]

Hi!! Okay thanks! And yes I think that’s correct.

6 0

3 years ago

What is the center and radius?<br><br> X^2+y^2+6x-6y=-14

Zolol [24]

Answer:

Therefore,

$Center\ is\ C(-3,3)\\and\\Radius= 2\ units$

Step-by-step explanation:

Given:

A Equation of a Circle that is

$x^{2} +y^{2}+ 6x-6y=-14$

Which can be written as

$x^{2} +y^{2}+ 6x-6y+14=0$

To Find:

Center C( -g , -f ) = ?

radius = r =?

Solution:

General Equation of a Circle is given as

$x^{2} +y^{2}+ 2gx+2fy+c=0$

On Comparing the Given equation with the General equation we get the following values,

$2g=6\ and\ 2f=-6\ and\ c=14\\\therefore g=\frac{6}{2}=3\\ \\\therefore f=\frac{-6}{2}=-3\\$

Now, Center and Radius for above circle is given as

$C(-g,-f)=(-3,-(-3))=(-3,3)\\and\\radius = r=\sqrt{(g^{2}+f^{2}-c )} = \sqrt{(3^{2}+(-3)^{2}-14)}\\\\\therefore radius = r=\sqrt{(18-14)} \\\\\therefore radius = r=\sqrt{4}=2\ unit\\$

Therefore,

$Center\ is\ C(-3,3)\\and\\Radius= 2\ units$

6 0

4 years ago