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Nikolay [14]
3 years ago
11

There are two spinners. The first spinner has three equal sectors labeled 1, 2, and 3. The second spinner has four equal sectors

labeled 3, 4, 5, and 6. Spinners are spun once. How many outcomes do not show an even number on the first spinner and show a 6 on the second spinner?
Mathematics
1 answer:
Tasya [4]3 years ago
4 0

Answer:

2 outcomes

Step-by-step explanation:

Let's list count all the possible outcomes:

(1,3) (1,4) (1,5) (1,6)

(2,3) (2,4) (2,5) (2,6)

(3,3) (3,4) (3,5) (3,6)

As expected, there are 12 (3x4) possible outcomes.

How many outcomes do not show an even number (so showing 1 or 3) on the first spinner and show a 6 on the second spinner?

There are two cases where 6 is on the second spinner and NOT an even number on the first spinner: (1,6) and (3,6)

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If 2x+y=8 and x-1=y then what is y? Please be detailed I want to know more then just the answer but how to solve
IgorLugansk [536]
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3 years ago
using the numbers 3, 5, and 8, can you write nine proper fractions and nine improper fractions? You may use each number only onc
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Answer:

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Where a is the numerator, and b is the denominator.

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3/5

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5/8

3/85

3/58

5/83

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8/35

8/53

You can see that in all of them the denominator is larger than the numerator.

The improper fractions are those where the numerator is equal or larger than the denominator.

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