Answer:
line1:y=2x+3
Gradient1=2
Let line2 be the line passes through (-4,1)and perpendicular to line1.
Because line2 and line1 are perpendicular, (gradient of line2) (gradient of line1) =-1
Gradient of line2=-1/2
Equation of line2:y-y1 =m(x-x1)
:y-1 =(-1/2)[x-(-4)]
:(y-1)(-2)=(x+4)
:-2y+2 =x+4
:-2y+2-x-4=0
:-x-2y-2 =0
:x+2y+2 =0
*notes:gradient=m
Answer:
A. x≥4 ( red on 4)
B. x≤4 ( red on 4)
C. x>4 (blue on 4)
D. x<4 (blue on 4)
Step-by-step explanation:
illustrated
A. x≥4 ( red on 4)
B. x≤4 ( red on 4)
C. x>4 (blue on 4)
D. x<4 (blue on 4)
First, distribute the minus sign across the second set. So you have:
x - y + 1 - x - y + 1
Now, we combine like terms:
x-x=0
-y-y=-2y
1+1=2
So we have -2y+2
Hope that helps.
A plane has two dimensions and extends infinitely in both dimensions.
