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tino4ka555 [31]
3 years ago
6

Please help please please please

Mathematics
1 answer:
Yuliya22 [10]3 years ago
4 0
I think its 7/21 because 7+6+8=21 which is the total and then the amount of green balls is 7 so 7/21
You might be interested in
Write a rule for g described by the transformation of the graph of f...
Svetlanka [38]

Answer:

g(x) = 4-4\sqrt{x}

Step-by-step explanation:

Given

f(x) = 4\sqrt{x}+1

1. 5 units down translation

2. Reflection in the x-axis

Required

Determine the resulting function g

1. 5 units down translation

This is defined by the rule:

A down translation is:

f'(x) = f(x) - b

Where b is the number of units.

So, we have:

f'(x) = 4\sqrt{x} + 1 - 5

f'(x) = 4\sqrt{x} -4

2. Reflection in the x-axis

For a function f(x),

When reflected over the x-axis, it becomes -f(x)

So:

g(x) = -f(x)

g(x) = -(4\sqrt{x} - 4)

g(x) = -4\sqrt{x} +4

g(x) = 4-4\sqrt{x}

4 0
3 years ago
If range of the function f(x) = 3x+2 is {5,8,11,14}, find the domain of the function
pentagon [3]

Answer:

{17,26,35,44}

Step-by-step explanation:

f(5) = 3(5)+2 = 17

f(8) = 3(8)+2 = 26

f(11) = 3(11)+2 = 35

f(14) = 3(14)+2 = 44

8 0
3 years ago
How to outline a proof
Sav [38]
I'll give you an example from topology that might help - even if you don't know topology, the distinction between the proof styles should be clear.

Proposition: Let
S
be a closed subset of a complete metric space (,)
(
E
,
d
)
. Then the metric space (,)
(
S
,
d
)
is complete.

Proof Outline: Cauchy sequences in (,)
(
S
,
d
)
converge in (,)
(
E
,
d
)
by completeness, and since (,)
(
S
,
d
)
is closed, convergent sequences of points in (,)
(
S
,
d
)
converge in (,)
(
S
,
d
)
, so any Cauchy sequence of points in (,)
(
S
,
d
)
must converge in (,)
(
S
,
d
)
.

Proof: Let ()
(
a
n
)
be a Cauchy sequence in (,)
(
S
,
d
)
. Then each ∈
a
n
∈
E
since ⊆
S
⊆
E
, so we may treat ()
(
a
n
)
as a sequence in (,)
(
E
,
d
)
. By completeness of (,)
(
E
,
d
)
, →
a
n
→
a
for some point ∈
a
∈
E
. Since
S
is closed,
S
contains all of its limit points, implying that any convergent sequence of points of
S
must converge to a point of
S
. This shows that ∈
a
∈
S
, and so we see that →∈
a
n
→
a
∈
S
. As ()
(
a
n
)
was arbitrary, we see that Cauchy sequences in (,)
(
S
,
d
)
converge in (,)
(
S
,
d
)
, which is what we wanted to show.

The main difference here is the level of detail in the proofs. In the outline, we left out most of the details that are intuitively clear, providing the main idea so that a reader could fill in the details for themselves. In the actual proof, we go through the trouble of providing the more subtle details to make the argument more rigorous - ideally, a reader of a more complete proof should not be left wondering about any gaps in logic.

(There is another type of proof called a formal proof, in which everything is derived from first principles using mathematical logic. This type of proof is entirely rigorous but almost always very lengthy, so we typically sacrifice some rigor in favor of clarity.)

As you learn more about a topic, your proofs typically begin to approach proof outlines, since things that may not have seemed obvious before become intuitive and clear. When you are first learning it is best to go through the detailed proof to make sure that you understand everything as well as you think you do, and only once you have mastered a subject do you allow yourself to omit obvious details that should be clear to someone who understands the subject on the same level as you.
3 0
3 years ago
A triangle with vertices at A(20, –30), B(10, –15), and C(5, –20) has been dilated with a center of dilation at the origin. The
Kobotan [32]

Answer:

One-fifth

Step-by-step explanation:

step 1

Find the distance between the origin and the point B

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

O (0,0) and B(10, –15)

substitute

d=\sqrt{(-15-0)^{2}+(10-0)^{2}}

d=\sqrt{325}\ units

step 2

Find the distance between the origin and the point B'

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

O (0,0) and B'(2,-3)

substitute

d=\sqrt{(-3-0)^{2}+(2-0)^{2}}

d=\sqrt{13}\ units

step 3

Find the scale factor of the dilation

The scale factor is equal to divide the length of segment OB' by the length of segment OB

so

\frac{\sqrt{13}}{\sqrt{325}}=\frac{1}{5}

so

One-fifth

4 0
3 years ago
Read 2 more answers
The table below shows all of the possible outcomes for rolling two six-sided number cubes.
CaHeK987 [17]

Answer: 36

Step-by-step explanation:

7 0
3 years ago
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