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arsen [322]
3 years ago
5

The average typing speed of a stenographer is 100 words per minute. How many words would a stenographer type in 4⁄5 of a minute

if typing at the average speed?
Mathematics
2 answers:
jeyben [28]3 years ago
6 0

Answer:

80 words. 4/5 of 100 is 80

Step-by-step explanation:

asambeis [7]3 years ago
4 0

Answer: 80

5th of a minute is 12 seconds so 4/5 equals 48 seconds.

100 words per minute equals 1.66666667 words per second ( 100 divided by 60)

So 1.66666667 X 48 = 80)

Step-by-step explanation:

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Look at the figure XYZ in the coordinate plane. Find the perimeter of the figure rounded to the nearest tenth.
ki77a [65]

the distance form X to Y is clearly -6 to 0 is 6 units, and 0 to 8 is 8 units, so 6 + 8 = 14 units.

now, for XZ and ZY we can simply use as stated, the distance formula to get those and then add them all to get the perimeter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ X(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ XZ=\sqrt{[5-(-6)]^2+[8-2]^2}\implies XZ=\sqrt{(5+6)^2+(8-2)^2} \\\\\\ XZ=\sqrt{121+36}\implies \boxed{XZ=\sqrt{157}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad Y(\stackrel{x_2}{8}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ ZY=\sqrt{(8-5)^2+(2-8)^2}\implies ZY=\sqrt{9+36}\implies \boxed{ZY=\sqrt{45}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{perimeter}{14+\sqrt{157}+\sqrt{45}}\qquad \approx \qquad 33.2

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3 years ago
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<span>20, 21, 22, 24, 25, 26, 27, 28, 30. hope that helped</span>
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