Answer: -104
Explanation: x=-9 y=2
2(y-3xy)
=2(2-3(-9)(2))
=4-2(3(-18))
=4-108
=-104
Hope it helped
Answer:
0 < t < 
After 1.67 days the stocks would be sold out.
Step-by-step explanation:
The price of a certain computer stock after t days is modeled by
p(t) = 100 + 20t - 6t²
Now we will take the derivative of the given function and equate it to zero to find the critical points,
p'(t) = 20 - 12t = 0
t = 
t =
days
Therefore, there are two intervals in which the given function is defined
(0,
) and (
, ∞)
For the interval (0,
),
p'(1) = 20 - 12(1) = 20
For the interval (
, ∞),
p'(2) = 20 - 12(2) = -4
Positive value of p'(t) in the interval (0,
) indicates that the function is increasing.
0 < t < 
Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.
F(x)=2x+8
F(-1.8)=2(-1.8)+8
f(-1.8)=-3.6+8
f(-1.8)=4.4
Using the normal distribution, it is found that:
a) The pilot is at the 72th percentile.
b) 19.13% of pilots are unable to fly.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
.
Item a:
The percentile is the <u>p-value of Z when X = 74.2</u>, hence:


Z = 0.59
Z = 0.59 has a p-value of 0.7224.
72th percentile.
Item b:
The proportion that is able to fly is the <u>p-value of Z when X = 78 subtracted by the p-value of Z when X = 70</u>, hence:
X = 78:


Z = 2
Z = 2 has a p-value of 0.9772.
X = 70:


Z = -0.96
Z = -0.96 has a p-value of 0.1685.
0.9772 - 0.1685 = 0.8087 = 80.87%.
Hence the percentage that is unable to fly is:
100 - 80.87 = 19.13%.
More can be learned about the normal distribution at brainly.com/question/4079902
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