What is the equivalent expression to this 9(2a+1)

The Boy scouts spent 10/12 hour doing their daily exercises. They only used 1/4 hour in hiking in. How much time did they use fo

KengaRu [80]

Answer:

35

Step-by-step explanation:

10/12 of an hour/60 minutes = 50 minutes so they spent that amount of time doing daily exercises

1/4 of an hour/60 minutes = 15 minutes so they spend that time hiking

subtract the 15 mins of hiking from the total 50 of exercises = 35 for other body exercises

Hope this helped!

4 0

2 years ago

Read 2 more answers

Help me please thank you

katen-ka-za [31]

Answer:

Step-by-step explanation:

A+N+J=310

A=N*2 =>N=A/2

N=J*3 =>J=N/3

N=?

N*2+N+N/3=310

3N+N/3=310

(9N+N)/3=930/3

10N=930

N=930/10

N=93

will be nice if you give me brainlies.Good luck!

7 0

3 years ago

38% of a companys employees prefer coffee to tea . if the company has 7000 employees , how many prefer coffee to tea/

77julia77 [94]

So if 7000 is the 100%, how much is the 38%?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
7000&100\\
x&38
\end{array}\implies \cfrac{7000}{x}=\cfrac{100}{38}\implies \cfrac{7000\cdot 38}{100}=x$

8 0

3 years ago

Read 2 more answers

Part 1: Linear Systems and Line Segments

Nataly_w [17]

Answer:

y=8(x−8)(x+0.5)

Step-by-step explanation:

Part 1: Linear Systems and Line Segments

Create and attach a 1 page ‘cheat’ sheet for the Linear Systems Unit.

Solve each system by graphing:

y = x+2, y = 4-1

2x – y + 9 = 0, x + y – 3 = 0

Solve by substitution:

x – 2y = 4, 2x – 3y = 7

Solve by elimination:

3x + 8y = -3, x + 8y = -5

4x – 5y = -22, 5x +6y = -3

Find the length of the line segment joining each pair of points. (Express to nearest 10th of a unit)

(2,5) and (5,7)

(-1, -3) and (-2, -4)

Find the midpoint of each line segment.

M (-2, 2), P (4, 8)

A (3, 3), J (-9, 3)

The Midpoint of AB is M(-2, 1). IF A(-7, 3), what are the coordinates of B?

Page Break

Part 2: Trigonometry

Create and attach a 1 page ‘cheat’ sheet for the Trigonometry Unit.

Solve each right triangle:

Shape E

Shape F 62⁰ D

150 cm

ShapeText BoxA

Shape15⁰

ShapeB C

Page Break

Solve each triangle:

Shape L

58⁰

56⁰

M 19 cm N

ShapeJ

58⁰

18 mm 15 mm

K L

Khalid wants to be sure his boat is safely anchored. He knows that the angle of depression that the boat makes with the horizontal when anchored should be less than 12⁰. The boat is 100 m above the seabed and the anchor cable is 440 m long. Is Khalid safely anchored? Explain.

Part 3: Polynomials

Create and attach a 1 page ‘cheat’ sheet for the Polynomial Unit.

Simplify

(4x - 3) + (5x+4)

(2x2 – 3x + 4) – (x2 + 4x - 1)

(-6x3 yz2 )(-2xy2 z)

Factor, if possible

7x + 42

X2 + 7x + 12

3x2 = 12x = 9

X2 + 9

5x2 – 20x + 20

Page Break

Part 4: Quadratics

Create and attach a 1 page ‘cheat’ sheet for the Quadratics Unit.

Graph the data and write the relation in the form of

y=a(x−h)2

y=ax−h2

X

Y

-6

32

-5

18

-4

8

-3

2

-2

0

-1

2

Graph the data and write the relation in the form of

y=a(x−h)2

y=ax−h2

X

Y

-1

-8

0

-4.5

1

-2

2

-0.5

3

0

4

-0.5

Graph the relation by plotting the vertex and 2 other points.

y=(x+1)2−1

y=x+12−1

y=−2(x−6)2+2

y=−2x−62+2

For each, write the relation in standard form:

y=ax2+bx+c

a=2, b=5, y intercept = 11

y=5x2+bx+c

, vertex at (1, 4)

a=−3

, passes through (2, 11) and (0, -5)

Factor:

x2−17x+66

x2−3x−18

x2+13x

x2−9

Find the zeros.

y=(x+3)(x−3)

y=x+3x−3

y=−10x2

y=8(x−8)(x+0.5)

4 0

3 years ago

A cellphone provider has the business objective of wanting to estimate the proportion of subscribers who would upgrade to a new

stiv31 [10]

Answer:

$z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913$

$p_v =P(z>3.913)=0.000046$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=135 represent the subscribers that would upgrade to a new cellphone at a reduced cost

$\hat p=\frac{135}{500}=0.27$ estimated proportion of subscribers that would upgrade to a new cellphone at a reduced cost

$p_o=0.2$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is higher than 0.2 or not.:

Null hypothesis: $p \leq 0.2$

Alternative hypothesis: $p > 0.2$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.913)=0.000046$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

6 0

4 years ago