Answer: 26
Step-by-step explanation:
lets replace a and b with the numbers provided
2+4(2+4)=2+4(6)=2+24=26
Sorry if it is messy but if you dont understand feel free to ask .
Part A you would use 200-L ( since you have 400 feet total 200 feet would equal length plus width)
Part B 200 - 80 = 120
Part C 200-90 = 110
area = 90 x 110 = 9900 square feet
Answer:
- 2(L +W) ≤ 600
- W ≤ 200
- L ≥ 2W
Step-by-step explanation:
We assume the problem wording means the length is to be at least 2 times <em>as long as</em> the width. (<em>Longer than</em> usually refers to a difference, not a scale factor.)
If we let "W" and "L" represent the width and length, respectively, then we can translate the problem statement to ...
2(L + W) ≤ 600 . . . . . . the perimeter is twice the sum of length and width
W ≤ 200 . . . . . . . . . . . . the width is at most 200 inches
L ≥ 2W . . . . . . . . . . . . . the length is at least twice the width
Answer:
a) 3n^2 + 11n + 8
b) 350
Step-by-step explanation:
10) 3(10^2)+ 5*10 = 350
n+1) 3(n+1)^2 + 5(n+1)
3(n^2 + 2n + 1) + 5n+5
3n^2 + 6n+3 + 5n + 5
3n^2 + 11n + 8
