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Sidana [21]
4 years ago
7

Multiply 5x^2-6x+2 4x^2-3x

Mathematics
2 answers:
mixas84 [53]4 years ago
8 0

Answer:

20x^{4}-39x^{3} +26x^{2}-6x\\

Step-by-step explanation:

Multiply the two polynomials by multiplying each term

(5x^{2} -6x+2)(4x^{2} -3x)\\5x^2*4x^2+5x^2(-3x)+(-6)*4x^2+(-6x)(-3x)+2*4x^2+2(-3x)\\20x^{4}-39x^{3}  +26x^{2} -6x\\

Whitepunk [10]4 years ago
4 0

Answer:

20x^4-39x^3+26x^2-6x

Step-by-step explanation:

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Select the correct answer.
Ganezh [65]

Answer:

C. 6x(x² + 4x - 12)

Step-by-step explanation:

Factor 6x^{2} out of 6x^{4}

<em> </em>6x^{2}<em> (</em>x^{2}<em>) + </em>6x^{2}<em> + </em>24x^{3} - 72x^{2}<em />

<em> </em>6x^{2}<em> (</em>x^{2}<em>) + </em>6x^{2}<em> (</em>4x<em>) </em>-72x^{2}<em />

<em> </em>6x^{2}<em> (</em>x^{2}<em>) + </em>6x^{2}<em> (</em>4x<em>) + </em>6x^2 (-12)

6x^{2}<em>(</em>x^{2}<em> + </em>4x<em>) +  </em>6x^{2}<em> (-12)</em>

6x^{2}<em>(</em>x^{2}<em> + </em>4x<em> - 12 )</em>

8 0
3 years ago
Read 2 more answers
the sum of 3 consecutive integers is 29 less than 5 times the smallest number. find the three numbers
allochka39001 [22]

x + x + 1 + x + 2 = 5x - 29

Combine like terms.

3x + 3 = 5x - 29

Subtract 3x from both sides.

3 = 2x - 29

Add 29 to both sides.

32 = 2x

Divide both sides by 2.

16 = x

<h3>The first digit is 16.</h3><h3>The second digit is 17.</h3><h3>The third digit is 18.</h3>
6 0
4 years ago
How do these numbers compare?
vampirchik [111]

Answer:

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Step-by-step explanation:

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3 years ago
How many meal combinations?
Flura [38]

Answer:

120

Step-by-step explanation:

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5 0
3 years ago
3/4+n=-5/2 whats the answer for n
dmitriy555 [2]
Your answer would be -13/4.
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3 years ago
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