4 9/20 that is the mixed number of 4.45
Answer:
33.94 cms of ribbon
Step-by-step explanation:
Because you need two diagonals to form the x, therefore the amount of ribbon needed is the sum of the distance of both diagonals.
When crossing the diagonal, a rectangular angle is formed, where the diagonal would be the hypotenuse, we know that the distance of the hypotenuse can be calculated by means of the legs, which we know its value (12):
d ^ 2 = a ^ 2 + b ^ 2
a = b = 12
d ^ 2 = 12 ^ 2 + 12 ^ 2
d ^ 2 = 288
d = 288 ^ (1/2)
d = 16.97
16.97 cm is what it measures, a diagonal, therefore tape is needed:
16.97 * 2 = 33.94
A total of 33.94 cms of ribbon is needed
Answer from jmonterrozar
Answer:
Step-by-step explanation:
I've already done this question for you. You must be reposting it because the answer was not correct according to the way the computer was programmed to get the answer. I can only think that you don't count the interface between the cube and the larger figure at all. So let's do it that way.
Start with the cube.
The formal equation is Area = 5 * s^2
It has 5 equal sides each one measuring 3 * 3
Area = 5 * 3^2 = 45
Now go to the other figure
The front and back face measure 14*6*2 = 168
Left and Right Sides are 2 * 6 * 8 96
Top and Bottom 2 * 14 *8 224
Don't count the base of the cube at all so subtract 3*3 -9
Total 524
If that does not work, please leave a note at the bottom of this question.
They did not state exactly what the width or length is. So in this case, let's name the number of width to be x. And thus we can derive to the conclusion of,
Width : x
Length : x-44 (from the 1st sentence of question)
So, We all know that a rectangle has 2 Lengths and 2 widths. So we can derive the conclusion that,
2(x)+2(x-44)=150150
2x+2x-88=150150
4x-88= 150150
4x= 150150+88=150238
4x=150238
x= 150238÷4
=37559.5
