The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.
<h3>What is an area bounded by the curve?</h3>
When the two curves intersect then they bound the region is known as the area bounded by the curve.
The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0
The intersection points will be
y₁ = y₂
4 - 4x² = 0
x = ±1
Then the area bounded by the curves will be
![\rm Area = \int _{-1}^1 (y_1- y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \](https://tex.z-dn.net/?f=%5Crm%20Area%20%3D%20%5Cint%20_%7B-1%7D%5E1%20%28y_1-%20%20y_2%29%20dx%5C%5C%5C%5CArea%20%3D%20%5Cint%20_%7B-1%7D%5E1%20%284%20-%204x%5E2%29%20dx%5C%5C%5C%5CArea%20%3D%20%5Cleft%20%5B%204x%20%20-%20%5Cdfrac%7B4x%5E3%7D%7B3%7D%20%5Cright%20%5D_%7B-1%7D%5E1%5C%5C%5C%5CArea%20%3D%204%20%5Cleft%20%28%201%20%2B%201%20%5Cright%20%29%20-%20%5Cdfrac%7B4%7D%7B3%7D%20%5Cleft%20%28%201%5E3%20-%20%28-1%29%5E3%20%5Cright%20%29%5C%5C%5C%5CArea%20%3D%208%20-%20%5Cdfrac%7B8%7D%7B3%7D%5C%5C%5C%5CArea%20%3D%20%5Cdfrac%7B16%7D%7B3%7D%20%3D%205.333%20%5C)
More about the area bounded by the curve link is given below.
brainly.com/question/24563834
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Where is the table i dont see it
19 chairs.
650-176 is 474 and 474 divided by 25 is 18.96 so round up and 19 or 18 per row
It is really easy. You have 2 numbers and a multiplication sign. Multiply them together. I am not going to give you the answer I am going to help you.
8 X 9 =
Answer:
6.2 units
Step-by-step explanation:
The mnemonic SOH CAH TOA is intended to remind you of the relations between trig functions and sides of a right triangle.
<h3>Common segment</h3>
To find the value of x in this figure, we need to know the length of the common segment between the two triangles. That segment is opposite the 53° angle, so can be found using the sine relation:
Sin = Opposite/Hypotenuse
Opposite = Hypotenuse × Sin = 30·sin(53°) ≈ 23.9591
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<h3>Missing measure</h3>
The side marked x is adjacent to the marked angle in that triangle, so the relevant relation is ...
Cos = Adjacent/Hypotenuse
Adjacent = Hypotenuse × Cos = 23.9591·cos(75°) ≈ 6.20106
The length of the side marked x is about 6.2 units.
