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3 years ago

It took 5.5 hours to drive 154 miles. What was the average rate of speed?

Mathematics

1 answer:

Leya [2.2K]3 years ago

4 0

28 miles per hour is your answer 154 divided by 5.5, simple math hon :) good luck.

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Where is the constant on here? 12+ x - 3.7 - 8y + 1/3

SCORPION-xisa [38]

12-3.7+(1/3)=constant
259/30=constant

6 0

3 years ago

How do you find the midpoint formula

koban [17]

The formula is x1+x2 divided by 2 and y1+y2 divided by 2.I hope this is what you where looking for

6 0

3 years ago

Find a polynomial function of degree 3 with 2, i, -i as zeros.

sergiy2304 [10]

Answer:

$p(x)= x^3-2x^2+x-2$

Step-by-step explanation:

Here we are given that a polynomial has zeros as 2 , i and -i . We need to find out the cubic polynomial . In general we know that if $\alpha , \ \beta \ \& \ \gamma$ are the zeros of the cubic polynomial , then ,

$\sf \longrightarrow p(x)= (x -\alpha )(x-\beta)(x-\gamma)$

Here in place of the Greek letters , substitute 2,i and -i , we get ,

$\sf\longrightarrow p(x)= (x -2 )(x-i)(x+i)$

Now multiply (x-i) and (x+i ) using the identity (a+b)(a-b)=a² - b² , we have ,

$\sf \longrightarrow p(x)= (x-2)\{ x^2 - (i)^2\}$

Simplify using i = √-1 ,

$\sf \longrightarrow p(x)= (x-2)( x^2 + 1 )$

Multiply by distribution ,

$\sf \longrightarrow p(x)= x(x^2+1) -2(x^2+1)$

Simplify by opening the brackets ,

$\sf\longrightarrow p(x)= x^3+x-2x^2-2$

Rearrange ,

$\sf\longrightarrow \underline{\boxed{\blue{\sf p(x)= x^3-2x^2+x-2}}}$

4 0

2 years ago

5.08 Mid-Unit Assessment: Solid Figures Pool 1 Question 5

qaws [65]

Answer:

600 ft^3

Step-by-step explanation:

8 0

3 years ago

The domain of f(x) is the set of all real values except 7, and the domain of g(x) is the set of all real values except –3. Which

bija089 [108]

Answer:

The set of all real values except 7

Step-by-step explanation:

We are given that,

Domain of the function f(x) is 'the set of all real values except 7'.

Domain of the function g(x) is 'the set of all real values except -3'.

It is required to find the domain of $(g\circ f)(x)$ .

Now, we know that,

The composition $(g\circ f)(x)$ of functions $f(x)$ and $g(x)$ will be defined where the function $f(x)$ is defined.

Since, the domain of f(x) is 'the set of all real values except 7'.

Thus, the domain of $(g\circ f)(x)$ is also 'the set of all real values except 7'.

4 0

3 years ago