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skelet666 [1.2K]
2 years ago
15

A spherical balloon is inflated so that its volume is increasing at the rate of 2 ft3/min. How rapidly is the diameter of the ba

lloon increasing when the diameter is 1.7 feet?
Mathematics
1 answer:
ad-work [718]2 years ago
5 0
According to the question requirements 

v= 4/3*pi*r^3

dv/dt = 4*pi*r^2*dr/dt

when 
d= 1.7
r= 0.85
and 
dv/dt = 2

2= 4*pi*(0.85)^2*dr/dtthus the the speed of increasing of the balloon's diameter is 
dr/dt = 1/(2pi*(0.85)^2)

=<span>0.2203 ft/min</span>


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The answer is B

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The extreme value of y = (x - h)² - c is the vertex of the equation.

<h3>What are extreme values of a function?</h3>

The extreme values of a function are either the maximum or minimum values of the function.

<h3>The equation of a parabola in vertex form</h3>

The equation of a parabola in vertex form with vertex (h', k) is given by

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Since y = (x - h)² - c is the equation of a parabola in vertex form, comparing with y = a(x - h')² + k,

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Now, since a = 1 > 0, (h, -c) is a minimum point.

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The missing figure is attached down

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Step-by-step explanation:

<em>Let us explain the linear relation</em>

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→ The line represents container A is steeper more than the line

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