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mel-nik [20]
3 years ago
9

FIRST RIGHT GETS BRAINLIEST

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
7 0

Answer:

Red is sus

Step-by-step explanation:

Bezzdna [24]3 years ago
7 0

Answer: naah i think brown is sus he faked electrical vote him out

Step-by-step explanation:

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What is 4x-2 equal to??
dsp73
If you mean 4 times -2 thats -8 if you mean 4x-2 then you cant do that
7 0
3 years ago
Help me no links please
REY [17]

Time (min) Distance (km)

2 6

6 18

8 24

15 45

5 0
3 years ago
Read 2 more answers
use the pythagorean theorem to find the missing side length. 2 write sin, cosine, tangent of each angel.​
Harlamova29_29 [7]

Answer:

1) x=5\sqrt{3}

2) sin(a)=5\sqrt{3}/14

sin(b)=11/14

cos(a)=11/14

cos(b)=5\sqrt{3}/14

tan(a)=5\sqrt{3}/11

tan(b)=11/5\sqrt{3}

Step-by-step explanation:

 The Pythagorean Theorem is:

a^{2}=b^{2}+c^{2}

Where a is the hypotenuse and b and c are the legs.

The missing side lenght is one of the legs, then you must solve for one of them. Therefore, this is:

x=\sqrt{(14yd)^{2}-(11yd)^{2}}=5\sqrt{3}yd

MEASURE OF ANGLE:

Keep the identities on mind:

sin\alpha=opposite/hypotenuse

cos\alpha=adjacent/hypotenuse

tan\alpha=opposite/adjacent

Susbstitute values, then:

sin(a)=5\sqrt{3}/14

sin(b)=11/14

cos(a)=11/14

cos(b)=5\sqrt{3}/14

tan(a)=5\sqrt{3}/11

tan(b)=11/5\sqrt{3}

4 0
4 years ago
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HELP please! I need Help. Pre-calc. I'm not sure how to solve this. 50 Points! Please It will be appreciated.
Brums [2.3K]

\large{\mathcal{QUESTION:}}

An elliptical mirror has an eccentricity of 0.8. The mirror is surrounded by a 2-inch wide golden frame and is 34 inches tall including the frame. If a replacement mirror is being cut from a rectangular sheet of glass, what is the minimum dimensions needed for the sheet of glass?

\large{\mathcal{ANSWER:}}

<u>B</u><u>.</u><u> </u><u>1</u><u>7</u><u> </u><u>i</u><u>n</u><u>c</u><u>h</u><u>e</u><u>s</u><em><u> </u></em><u>b</u><u>y</u><u> </u><u>8</u><u> </u><u>i</u><u>n</u><u>c</u><u>h</u><u>e</u><u>s</u>

5 0
2 years ago
Solve for the indicated variable
GrogVix [38]

Answer:

X_1=\frac{YX_2}{X_2-Y} \\\\

Step-by-step explanation:

\frac{1}{Y}=\frac{1}{X_1}+\frac{1}{X_2}

First subtract the 1/x2

\frac{1}{Y} - \frac{1}{X_2}=\frac{1}{X_1}

Next subtract the fractions on the left

\frac{X_2-Y}{YX_2}=\frac{1}{X_1}\\

Next Multiply by x1

\frac{(X_1)X_2-Y}{YX_2}=1\\

Next divide both sides by the remaining parts (not x1)

X_1=\frac{YX_2}{X_2-Y} \\\\

7 0
3 years ago
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