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JulsSmile [24]
3 years ago
7

I need help please can you ?

Mathematics
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

yo

Step-by-step explanation:

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Manuel borrowed $1,500 from his bank and signed a
Mice21 [21]

Answer:

The total interest to pay back on the loan is $122.40

Step-by-step explanation:

Here. we want to get the amount of interest on the loan

We are going to use the compound interest formula here

A = P(1 + r/n)^nt

where A is the amount to be paid back

P is the amount borrowed called the principal which is $1,500

r is the interest rate which is 4% annually

This is same as 4/100 = 0.04

n is the number of times the interest will be compounded per year ; annually means yearly and so for this case, n = 1

t is the number of years = 2

So we have;

A = 1500(1 + 0.04/1)^(2)(1)

A = 1500(1.04)^(2)

A =$ 1,622.40

So the amount of interest is the difference between the amount borrowed and the value to pay back

That will be;

$1,622.40 - $1,500

= $122.40

3 0
2 years ago
What is the awnser and thank you!
adell [148]

Answer:

I believe it is A

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
Write an expression for: the product of 4 and a number. Use x as the variable. Who ever gets it correct first gets brainliest.
maksim [4K]
X(4*1) because I’m just doing what I’m told.
7 0
2 years ago
A store owner paid $15 for a book. She marked up the price of the book by 40% to determine its selling price. What is the sellin
densk [106]

Answer:

the selling price is 21 dollars

7 0
2 years ago
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