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3 years ago

Solve 8x-7y=18 for y?

Mathematics

1 answer:

adelina 88 [10]3 years ago

6 0

Answer:

y = 8/7x -18/7

Step-by-step explanation:

8x-7y=18

Subtract 8x from each side

8x-8x-7y=-8x+18

-7y = -8x+18

Divide each side by -7

-7y/-7 = ( -8x+18)/-7

y = 8/7x -18/7

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Assume that the heights of boys in a high school basketball tournament are normally distributed, with mean 70 inches and standar

Annette [7]

Answer: 20

Step-by-step explanation:

We assume that the heights of boys in a high school basketball tournament are normally distributed.

Given : Mean height of boys : $\mu=70$ inches.

Standard deviation: $\sigma=2.5$ inches.

Let x denotes the heights of boys in a high school basketball tournament .

Then the probability that a boy is taller than 70 inches will be :-

$P(x> 70)=1-P(x\leq70)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{70-70}{2.5})\\\\=1-P(z\leq0)=1-0.5=0.5\ \ \text{[by using z-value table]}$

Now, the expected number of boys in a group of 40 who are taller than 70 inches will be :-

$40\times0.5=20$

Hence, the expected number of boys in a group of 40 who are taller than 70 inches=20

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