Question

Find the x-intercepts of the following parabola. y = -4x2 + 8x + 12

Answer 1

Answer:

Option B

Step-by-step explanation:

Equation of a parabola is given as y = -4x² + 8x + 12

We have to find the x-intercepts, of the parabola.

for any point on x-axis y coordinates will be zero.

So put placing y = 0 in the equation.

0 = -4x² + 8x + 12

-4(x² - 2x - 3) = 0

x² - 2x - 3 = 0

x² - 3x + x - 3 = 0

x ( x-3) + 1( x - 3) = 0

( x+1 ) ( x - 3 ) = 0

( x + 1 ) = 0 ⇒ ( x = -1 )

( x - 3 ) = 0 ⇒ ( x = 3 )

points on x-axis will be ( -1, 0 ) & ( 3, 0 )

Option B is the answer.

Answer 2

B. is the answer dude