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jeka57 [31]
4 years ago
12

Please help with #22! You don’t have to fully explain.

Mathematics
2 answers:
erik [133]4 years ago
4 0
3.5 strip As will fit into Strip b. 2/7 strip Bs will fit into strip A
Zanzabum4 years ago
3 0
It would take 2/7 of strip b to make strip a and 3 1/2 strip As to make a strip B
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That you're positive that you should be trying out these difficult math questions, let’s get right to it! The answers to these q
kirill [66]

Answer:

that you're positive that you should be trying out these difficult math questions, let’s get right to it! The answers to these questions are in a separate section below, so you can go through them all at once without getting spoiled.

#1:

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#2:

body_ACT_0506_-_59

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body_ACT_0809_-_38_J

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body_ACT_0809_-_54

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body_ACT_0809_-_55-1

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#8:

body_ACT_0809_-_60

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body_ACT_1112_-__48-1

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body_ACT_1112_-_45

#11:

body_ACT_1112_-_51-1

#12:

body_ACT_1112_-_52

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body_ACT_1314_-_55-1

Step-by-step explanation:

6 0
3 years ago
Solve 5x-9y=13 for y.
scoundrel [369]

Answer:

y =  \frac{5x - 13}{9}

Step-by-step explanation:

5x - 9y = 13 \\  5x - 13 = 9y \\  \frac{5x - 13}{9}   = \frac{9y}{9}  \\ y =  \frac{5x - 13}{9}

3 0
3 years ago
Find the x & y-intercepts of the function. f(x)=2(x−1)(x+2)(x−3)
ArbitrLikvidat [17]

Answer:

its in the image below because im too lazy to write it down.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A cube shaped box has the volume of 1 cubic meter. What is the area of one of it’s faces?
aleksandr82 [10.1K]
All of the sides are one
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3 years ago
How many ways are there to select a 5-card hand from a regular deck such that the hand contains at least one card from each suit
Snezhnost [94]

Answer:

There are 685464 ways of selecting the 5-card hand

Step-by-step explanation:

Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.

In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have {13 \choose 2} = 78 possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.

This gives us a total of 4*78*13³ = 685464 possibilities to select the hand.

6 0
3 years ago
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