Equation of a line is in the form y = mx+c, where m is the gradient and c is the y-intercept.
First step is to find the gradient.
m = (y2-y1)/(x2-x1)
= ( 5- -8)/(8-4) = 13/4
We have y = (13/4)x + c
Now we replace one of the coordinates to find c. Let’s replace (4,-8)
We have: -8 = (13/4)*4 + c
-8=13+c
c=-8-13= -21
Therefore, equation of line is:
y = (13/4)x - 21
Answer:
2.873375
Step-by-step explanation:
Answer:
<em>The area of a circle is πr2 and the perimeter (circumference) is 2πr</em>
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Answer:
Step-by-step explanation:
Given equation is,
x² + (p + 1)x = 5 - 2p
x² + (p + 1)x - (5 - 2p) = 0
x² + (p + 1)x + (2p - 5) = 0
Properties for the roots of a quadratic equation,
1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]
2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]
3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].
Discriminant of the given equation = 
For real roots,

p² + 2p + 1 - 8p + 20 > 0
p² - 6p + 21 > 0
For all real values of 'p', given equation will be greater than zero.
Answer:
[A]
Step-by-step explanation: