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Flura [38]
3 years ago
5

Giving out brainlist <3

Mathematics
2 answers:
Jobisdone [24]3 years ago
8 0

Answer:

12.5

Step-by-step explanation:

To find the volume you do L*H*W and I got.

satela [25.4K]3 years ago
3 0

Answer:

12.5

Step-by-step explanation:

to get it you have to multiply the length times the width times the height.

this method works for almost every 3D shape.

Hope this helps!!!

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Can y’all help me on question 39?!
erastova [34]
There ain’t no answer choices ?
3 0
3 years ago
70+Points please help
Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

(x-1)(x+3)(x-9)(x+1)(x-9)(x+1)(x+1)  

the above works out.  but not sure what other choices you had in the answer

6 0
3 years ago
Read 2 more answers
pls help!! A cylindrical vase has a diameter of 12 inches and a height of 12 inches. If the vase is filled 3/4 full of soil, how
il63 [147K]

Answer:

Answer: the vase contains 1017.36 inches³ of soil.

Step-by-step explanation:

We would apply thee formula for determining the volume of a cylinder which is expressed as

Volume = πr²h

Where

h represents the height of the cylinder

r represents the radius of the cylinder.

π is a constant whose value is 3.14

From the information given

Diameter = 12 inches

Radius = diameter /2 = 12/2

Radius = 6 inches

Height = 12 inches

Therefore,

Volume of the cylindrical vase =

3.14 × 6² × 12 = 1356.48 inches³

If the vase is filled 3/4 full of soil, then the volume of soil in the vase is

3/4 × 1356.48 = 1017.36 inches³

7 0
3 years ago
5(x-2)^2-29=-14 what does x equal
eimsori [14]

Answer:

x = 2+\sqrt{3}

Step-by-step explanation:

5(x-2)^2= 15 ←add 29 on both sides

(x-2)^2= 3  ← divide by 5 on both sides

x-2= \sqrt{3}   ← find the sq root of both sides

x= 2+\sqrt{3}   ← add 2 on both sides

8 0
4 years ago
Please help me with this
Ne4ueva [31]

Answer:

Option c

Step-by-step explanation:

A system of equations are given to us. And we need to solve them . The given system is

\begin{cases} y = 2x - 3\dots 1 \\ y = x^2 - 3\dots 2 \end{cases}

We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .

\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }

We got two values of x as 0 & 2 . Alternatively substituting these values we have ,

\implies y = 2 x - 3 \\\\\implies y = 2(0)-3 \qquad or \qquad y = 2(2)-3 \\\\\implies y = 0-3 \qquad or \qquad 4 - 3 \\\\\implies \red{ y = -3 , 1 }

Thefore the required answer is ,

\red{Option\:c} \begin{cases} (0,-3) \\ (2,1) \end{cases}

4 0
3 years ago
Read 2 more answers
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