Answer:
The ear length will be 11 cm.
Explanation:
To know about the ear length of F1 generation, we need to know that how much length in centimeters is contributed by each of the alleles. As we know, each allele has the same value for contributing to the effect of ear length, hence we can divide the ear length by 4 to get our results.
As 6 divided by 4 is 1.5 hence, the allele a and b contribute to 1.5 cm of the length of the ear.
6 divided by 4 is 4, hence the alleles And B contribute to 4 cm of the length of the ear.
The F1 generation will have AaBb genotype hence, the lenght will be 4+1.5+4+1.5 = 11 cm.
Yes! they would be your aunt and uncle!
Fewer hydrogen ions will be pumped into the Thylakoid when photosystem II being exposed to less sunlight more glucose molecules will be produced.
Photosystem II is the first membrane protein complex in oxygenic photosynthetic organisms in nature. It produces atmospheric oxygen to catalyze the photo-oxidation of water by using light energy. It oxidizes two molecules of water into one molecule of molecular oxygen.
Photosystem II the energy derived from absorption of photons is used to split water molecules to molecular oxygen and protons. The most important function of photosystem II (PSII) is its action as a water-plastoquinone oxido-reductase. At the expense of light energy, water is split, and oxygen and plastoquinol are formed.
To learn more about Photosystem II , here
brainly.com/question/13211869
#SPJ4
It looks correct to me. Good job
Answer:
The correct answer will be option-D.
Explanation:
In eukaryotes, the process of transcription takes place inside the nucleus whereas translation takes place in the cytosol. So, mRNA has to export to the cytosol from the nucleus.
Before export, the post-transcriptional modification takes place like 5' capping, 3' tailing and splicing mechanism.
The capping is done at 5' end by adding modified guanine (G) nucleotide which protects the mRNA from exonuclease activity and tailing is done at 3' end by adding adenine nucleotides which provides stability to the mRNA.Splicing removes the junk DNA called introns and joins the exons before export.
Thus, option-D is the correct answer.
