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bagirrra123 [75]
3 years ago
10

How do you know if you need to flip the inequality symbol in your final solution

Mathematics
1 answer:
uranmaximum [27]3 years ago
7 0

Answer:

The main situation where you'll need to flip the inequality sign is when you multiply or divide both sides of an inequality by a negative number. To solve, you need to get all the x-es on the same side of the inequality

Step-by-step explanation:

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I gvee brainlilsttttt
Lady_Fox [76]

Answer:

g or h whichever u think is best

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Calculate the value of A please ?
Cloud [144]
A=7d+13
A=7(4)+13
A= 28+13
A=41
8 0
2 years ago
How are the coordinates of the extreme value and the equation from part B in the form y=(x-h)^2-c related.
True [87]

The extreme value of y = (x - h)² - c is the vertex of the equation.

<h3>What are extreme values of a function?</h3>

The extreme values of a function are either the maximum or minimum values of the function.

<h3>The equation of a parabola in vertex form</h3>

The equation of a parabola in vertex form with vertex (h', k) is given by

y = a(x - h')² + k and its extreme values are

  • if a > 0  (h', k) is a minimum point and
  • if a < 0 (h', k) is a maximum point.

Since y = (x - h)² - c is the equation of a parabola in vertex form, comparing with y = a(x - h')² + k,

  • h = h'
  • -c = k and
  • a = 1.

So, the cooordinates of the vertex of y = (x - h)² - c is (h, -c).

Now, since a = 1 > 0, (h, -c) is a minimum point.

So, the extreme value of y = (x - h)² - c is the vertex of the equation.

Learn more about extreme value of a function here:

brainly.com/question/13464558

#SPJ1

4 0
2 years ago
Answer Please this is really important
trapecia [35]

Answer:

B) Parallel

Step-by-step explanation:

The lines have the same slope of \frac{4}{3}. This makes the lines parallel.

Hope it helps!

3 0
3 years ago
Read 2 more answers
Which equation has the same soultions as x^2+6×-7=0
blagie [28]
x^2+6x-7=0 \\   a=1 \\ b= 6 \\ c=-7 \\ \\  \boxed{\boxed{\Delta=b^2-4ac}} \\ \\ \Delta=6^2-4*1*(-7) \\ \Delta=36-(-28) \\ \Delta=64 \\ \Delta\ \textgreater \ 0 \Rightarrow \text{we have 2 solutions :} X_1 \ and X_2 \\ \\ \boxed{X_1= \frac{-b- \sqrt{\Delta} }{2a} } \Rightarrow X_1= \frac{-6-8}{2}=-7 \\ \\ \boxed{X_2= \frac{-b+ \sqrt{\Delta} }{2a} } \Rightarrow X_2= \frac{-6+8}{2} =1
4 0
3 years ago
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