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Ludmilka [50]
3 years ago
12

Which equation has the same soultions as x^2+6×-7=0

Mathematics
1 answer:
blagie [28]3 years ago
4 0
x^2+6x-7=0 \\   a=1 \\ b= 6 \\ c=-7 \\ \\  \boxed{\boxed{\Delta=b^2-4ac}} \\ \\ \Delta=6^2-4*1*(-7) \\ \Delta=36-(-28) \\ \Delta=64 \\ \Delta\ \textgreater \ 0 \Rightarrow \text{we have 2 solutions :} X_1 \ and X_2 \\ \\ \boxed{X_1= \frac{-b- \sqrt{\Delta} }{2a} } \Rightarrow X_1= \frac{-6-8}{2}=-7 \\ \\ \boxed{X_2= \frac{-b+ \sqrt{\Delta} }{2a} } \Rightarrow X_2= \frac{-6+8}{2} =1
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Answer:

5

Step-by-step explanation:

Tina started with $20, but had to spend $3.25 on the bat.

$20-$3.25 = $16.75, which is all she has left for rounds.

Each round costs $3.00

$16.75 divided by $3.00 comes out to 5.58 rounds, but since she can't play 1/2 a round, that means she could only play 5 rounds

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3 years ago
Show that (a+b)^2=4p^2​
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  • ( a + b)²
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2 years ago
5 over 12= x+1 over 4<br><br> please help!
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Equals 1/6
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Is 13 over 6 irrational number
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Step-by-step explanation:

5 0
3 years ago
Find the critical values: a. Determine the critical value z????/2 that corresponds to a level of confidence of 87%. (2 pts). b.
larisa86 [58]

Answer:

a) z_{\alpha/2}=-1.51 and z_{\alpha/2}=1.51

b) t_{\alpha/2}=-1.89 and t_{\alpha/2}=1.89

c) t_{\alpha/2}=-2.11

d) z_{\alpha/2}=-1.75 and z_{\alpha/2}=1.75

Step-by-step explanation:

Part a

On this case the confidence is 87% or 0.87 so the significance level is \alpha=1-0.87=0.13 and \alpha/2 =0.065. On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

We need values a,b on the normal standard distribution such that:

P(Z or P(Z>b)=0.065 and in order to find it we can use the following code in excel:

"NORM.INV(0.065,0,1)" or "NORM.INV(1-0.065,0,1)", and we see that the critical values z_{\alpha/2}=-1.51 and z_{\alpha/2}=1.51

Part b

On this case the confidence is 92% or 0.92 so the significance level is \alpha=1-0.92=0.08 and \alpha/2 =0.04. On this case we can assume that is a bilateral test or a confidence interval so we will have two critical values.

First we need to calculate the degrees of freedom given by:

df=n-1=15-1=14

We need values b,c on the t distribution with 14 degrees of freddom such that:

P(t_{(14)} or P(t_{(14)}>c)=0.04 and in order to find it we can use the following code in excel:

"T.INV(0.04,14)" or "T.INV(1-0.04,14)", and we see that the critical values t_{\alpha/2}=-1.89 and t_{\alpha/2}=1.89

Part c

The significance level is \alpha=0.025 and is a left tailed test. On this case we know that is a left tailed test so then we have just one critical value.

First we need to calculate the degrees of freedom given by:

df=n-1=18-1=17

We need a value c on the t distribution with 17 degrees of freddom such that:

P(t_{(17)}, and in order to find it we can use the following code in excel:

"T.INV(0.025,17)", and we see that the critical values t_{\alpha/2}=-2.11

Part d

The significance level is \alpha=0.08 and \alpha/2 =0.04. On this case we know that w ehave a two tailed proportion test, so we will have two critical values.

We need values a,b on the normal standard distribution such that:

P(Z or P(Z>b)=0.04 and in order to find it we can use the following code in excel:

"NORM.INV(0.04,0,1)" or "NORM.INV(1-0.04,0,1)", and we see that the critical values z_{\alpha/2}=-1.75 and z_{\alpha/2}=1.75

6 0
3 years ago
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