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Phoenix [80]
3 years ago
9

20% of 55 is what number

Mathematics
1 answer:
Vitek1552 [10]3 years ago
7 0
20% of 55 is 11

Workingout: 20%/100% = 0.2
                     0.2 x 55 = 11

:)

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seraphim [82]

Answer:

Its the first one | -9 | < | 9 |

Step-by-step explanation:

its false because both sides are identical

Hope this helps!

8 0
3 years ago
Read 2 more answers
Is everyone answering so we can ask more questions lol
kolbaska11 [484]

Answer: yes  

Step-by-step explanation:

Lol

8 0
3 years ago
Question 6. Solve -15 = x - 3
snow_lady [41]

Answer:

-12

Step-by-step explanation:

-15+3=x

-12=x

Hope u liked it

7 0
3 years ago
WILL MARK BRAINLIEST
777dan777 [17]

Answer:


Step-by-step explanation:

xy = k    

where k is the constant of variation.

We can also express the relationship between x and y as:

y =      

where k is the constant of variation.

Since k is constant, we can find k given any point by multiplying the x-coordinate by the y-coordinate. For example, if y varies inversely as x, and x = 5 when y = 2, then the constant of variation is k = xy = 5(2) = 10. Thus, the equation describing this inverse variation is xy = 10 or y = .

Example 1: If y varies inversely as x, and y = 6 when x = , write an equation describing this inverse variation.

k = (6) = 8  

xy = 8 or y =  

Example 2: If y varies inversely as x, and the constant of variation is k = , what is y when x = 10?

xy =  

10y =  

y = × = × =  

k is constant. Thus, given any two points (x1, y1) and (x2, y2) which satisfy the inverse variation, x1y1 = k and x2y2 = k. Consequently, x1y1 = x2y2 for any two points that satisfy the inverse variation.

Example 3: If y varies inversely as x, and y = 10 when x = 6, then what is y when x = 15?

x1y1 = x2y2  

6(10) = 15y  

60 = 15y  

y = 4  

Thus, when x = 6, y = 4.



2nd answer choice


constant of variation is xy. XY=23. If X=7 then Y=23/7.

3 0
3 years ago
Can someone please solve these?
JulijaS [17]

Answer:

Step-by-step explanation:

h = -6t^{2} +20t + 4

I will use calculus,  maybe that's not how you're supposed to do this

-12t +20 =0

12t = 20

t = 20 /12

t = 1 \frac{8}{12}

t = 1 \frac{2}{3}

there will be a max at  1.6666666666  seconds

-6*1.6666666666666^{2}  + 20 * 1.6666666666  +4

= 16.666666666666 + 33.333333333333 + 4

= - 16\frac{2}{3} + 33 \frac{1}{3} + 4

= 20\frac{2}{3}  feet max height ( not too high,  for a rocket)

time of flight:

0 = -6t^{2} +20t + 4

use quadratic formula to find t

-20 +- sqrt [ 20^{2} - 4*(-6)*4 ] / 2*(-6)

-20 +- sqrt [400 + 96 ] / -12

-20 +- sqrt [496 ] / -12

-20 +- 22.27105 / -12

try the negative option 1st

-42.27105 / -12

3.522 seconds.     time of flight

when will the rocket be at 12' ? :

12 = -6t^{2} +20t + 4

0 = -6t^{2} +20t -8

use quadratic formula again to find t

-20 +- sqrt [ 20^{2} - 4*(-6)*(-8) ] / 2*(-6)

-20 +- sqrt [ 400 - 192 ] / -12

-20 +- sqrt [208 ] / -12

-20 - 14.4222 / -12

-34.4222 / -12

2.8685 seconds ( on the way down)

and

-20 + 14.4222 / -12

-5.578 / - 12

0.4648  seconds ( on the way up )

6 0
3 years ago
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