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Neko [114]
3 years ago
11

Morgan deposits$1870 in an account that pays 2.05% simple interest for 4 years. Round to the nearest cent.

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
5 0

Answer:

$153.34

Step-by-step explanation:

Use formula:

I=P\cdot r\cdot t,

where I = Interest

P = Principal

r = rate

t = time

In your case,

P = $1,870

r = 0.0205 (or 2.05% as decimal)

t = 4

I = unknown

Hence,

I=1,870\cdot 0.0205\cdot 4\\ \\I=153.34

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If a = b and b = c, which statement must be true?
torisob [31]

Answer:

a=c

Step-by-step explanation:

This is because of the transitive property; which states that if a=b and b=c, then a=c.

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jonny [76]

Answer:

I don´t know fully but you add by ones on top and add by threes on the bottom

Step-by-step explanation:

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2 years ago
Please help me answer this.
TiliK225 [7]
8x2+6x-2

I think! because 8,6, and 2 are all divisible by 2

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3 years ago
Sally has just finished her thirty-fifth year with her company and is getting ready to retire. During her thirty-five years, Sal
olya-2409 [2.1K]

The <em>correct answer</em> is:

$19,153.26.

Explanation:

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Next we multiply this by the number we're taking the percent of:

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3 years ago
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Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
4 years ago
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