Answer:
W=5.3, l= 15.6
Step-by-step explanation:
Perimeter of a rectangle p=2(l+w)
P= 42
W= x
L= 5+2x therefore 42=2(5+2x+x)
42=10+6x , 32=6x
Make x subject of formula
X=32/6 x=5.3 there for w=5.3
Where L= 5+2x ; L=5+2(5.3)
L therefore = 15.6
Answer:
D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.
Step-by-step explanation:
The missing tables are:
First table
x: 0 1 2
f(x): 1 10 100
Second table
x: 1000 100 10
f^-1(x): 3 2 1
Option A is not correct because f(x) has a y-intercept at (0, 1)
If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct
Option C is not correct because the domain of f^-1(x) is associated with x values.
Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa
Jenna is correct. This is because the square root of 2 is an irrational number. And if the number is a prime number, the answer is less likely to have a rational square root.
Answer:
(-INFINITY , -2) (3 , INFINITY)
Function is positive when above the x axis
Function is below the x axis between -2 and 3
Answer: You get an answer?
Step-by-step explanation:
