Answer:
The length of each of the other two sides would be 3.1 cm
Step-by-step explanation:
<u><em>The options of the question are</em></u>
A. 3.1 cm
B. 3.2 cm
C. 4.2 cm
D. 6.1 cm
we know that
An isosceles triangle has two equal sides and two equal interior angles
Let
x -----> the length of each of the two equal sides in the isosceles triangle
The perimeter of one isosceles triangle is equal to

Remember that
To maximize the use of the wire, the perimeter of 6 earrings (3 pairs of earrings) must be equal to 50 cm
so

Solve for x




therefore
The length of each of the other two sides would be 3.1 cm
Ok so our original fraction is:

To simplify this fraction, look for instances where the values on the top and bottom can be reduced:
For example, 36 over 6 is the same as 6 over 1, so we can simplify the fraction so it is:

We can also eliminate the denominator by dividing the nominator by x^9 so:


And that is the simplified answer of the fraction
Hope this helped
No, the given sequence is not an arithmetic sequence.
What is Arithmetic Sequence ?
An arithmetic sequence is a list of numbers with a definite pattern. If you take any number in the sequence then subtract it by the previous one, and the result is always the same or constant then it is an arithmetic sequence.
In the above question,
The sequence is 3,5/2,3/2,-3/2,...
Take the 2nd term and minus the 1st term.
Now take the 3rd term and minus the 2nd term.
We can clearly notice that the differences are not same. Hence there is no common difference and therefore it's not an arithmetic sequence
To read about arithmetic sequence click here :
brainly.com/question/27079755
#SPJ4
Answer: 7(3m - 7n)
<u>Step-by-step explanation:</u>
Factor each term then see what value(s) they have in common:
21m - 49n
∧ ∧
3 · 7 · m 7 · 7 · n
Both terms have a 7 in common. What is left over after removing the 7?
21m: 7(3m)
49n: 7(7n)
GCF: 7 Leftovers: 3m <em>and</em> 7n
Factored form of expression is: 7(3m - 7n)
Answer:
There are 685464 ways of selecting the 5-card hand
Step-by-step explanation:
Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.
In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have
possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.
This gives us a total of 4*78*13³ = 685464 possibilities to select the hand.