If two triangles are in perspective, then the intersection points of corresponding sides of the two triangles will be______.

Mathematics

2 answers:

Irina18 [472]3 years ago

7 0

The answer on e2020 is B.) Collinear

Vikentia [17]3 years ago

5 0

I'm also just learning bout this ,
i'm sorry

but i should give so clue

in a projective plane, two triangles are said to be perspective from a point if the three lines joining corresponding vertices of the triangles meet at a common point called the center. ... Desargues' Theorem: If two triangles are perspective from a point then they are perspective from a line.

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The symbol is used to represent the ratio of the circumference to the diameter of a circle.

suter [353]

Answer:

Step-by-step explanation:

6 0

3 years ago

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Stan guessed on all 10 questions of a multiple-choice quiz. Each question has 4 answer choices. What is the probability that he

algol13

ANSWER
0.756

EXPLANATION

Let x represent number of correct answers.

We can find

$P(x = 0 \text{ or } x = 1)$

which leads us to

$P(x\ge 2) = 1 - P(x = 0\text{ or }x = 1)$

which uses the compliment of $P(x = 0\text{ or }x = 1)$ to find the probability of getting at least 2 questions correct.

Note that since $P(x=0)$ and $P(x=1)$ are mutually exclusive, we have

$P(x = 0\text{ or }x = 1) = P(x=0) + P(x=1)$

Then $P(x=0) = 3^{10}/4^{10} = (3/4)^{10}$ as we have $3^{10}$ to answer the questions incorrectly divided by the total $4^{10}$ to answer the questions.

Exactly 1 answer correct: $P(x=1) = {}_{10}C_1 \cdot(3/4)^9(1/4)^1$

Therefore

$\begin{aligned}
P(x \ge 2) &= 1 - P(x = 0\text{ or }x =1) \\
&=1 - \big[P(x=0) + P(x=1)\big] \\
&=1 - \left[ (3/4)^{10} + {}_{10}C_1 \cdot (3/4)^9(1/4)^1 \right] \\
&\approx 0.756
\end{aligned}$