Does anyone know what has integers as it's square root?

1 answer:

3 0

It shouldn't be too tough to find one of those, seeing that there are
an infinite number of them.

To create one, take any integer, positive or negative, and multiply it by itself.

Here are a few to put you in the mood:

1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, ...

784, 841, 900, 1024, 1225, 1600, 2500, 3600, 4900, 10000, 1 million, ...

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Hi what is the answer for this?

saw5 [17]

This is a common factor problem.

Pencils come in a pack of 12
Erasers come in a pack of 10

First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3

So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
We have (2*2*3) that comes from 12, and the only unique number that comes from the 10 is (5)
So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
60/12=5 packs of pencils
60/10= 6 packs of erasers

I hope this helps. Let me know if you have any questions!!

5 0

3 years ago

Read 2 more answers

Which set of graphs can be used to find the solution set to 3e* > >-x?

kobusy [5.1K]

The attached graph represents the solution set of $3e^x > \frac 12^x$