6.665 grams of the 13 grams remain after 8 hours.
<h3>How much of a 13 gram sample of iron-52 would remain after 8 hours?</h3>
The decay equation for the 13 grams of iron-52 is:

Where N is the amount of iron-52, and t is the time in years.
Where we used the fact that the half-life is exactly 8.3 hours.
Now, the amount that is left is given by N(8h), so we just need to replace the variable t by by 8 hours, so we get:

So 6.665 grams of the 13 grams remain after 8 hours.
If you want to learn more about half-life:
brainly.com/question/11152793
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Answer:
And rounded up we have that n=1068
Step-by-step explanation:
For this case we have the following info given:
the margin of error desired
the level of confidence given
The margin of error for the proportion interval is given by this formula:
(a)
the critical value for 95% of confidence is 
We can use as estimator for the population of interest
. And on this case we have that
and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
And replacing into equation (b) the values from part a we got:
And rounded up we have that n=1068
Answer:
Step-by-step explanation:
It's too bad about this problem. It's a fair game if you get paid the same amount that you have to pay if you lose.
You win 2 ways
- H - H
- T - T
- Probability 1/2
You lose 2 ways.
- H - T
- T - H
- Probability 1/2
Expectation
E = 1/2 * 3 - 1/2 * 4
E = 1.5 - 2
E = -0.5
Which means that you should expect to lose 0.5 dollars every time you play this dreadful game.
Answer:
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
F(x) 0.17 0.04 0.65 0.91 1
Step-by-step explanation:
Given that;
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
cumulative distribution function can be calculated by; be cumulatively up the value of p(x) with the values before it;
so
x F(x)
0 P(X = 0) = 0.17
1 P(X = 0) + P(X = 1) = 0.17 + 0.23 = 0.4
2 P(X = 0) + P(X = 1) + P(X = 2) = 0.17 + 0.23 + 0.27 = 0.65
3 P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.17 + 0.23 + 0.27 + 0.24 = 0.91
4 P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.17 + 0.23 + 0.27 + 0.24 + 0.09 = 1
Therefore, cumulative distribution function f(x) is;
(X) 0 1 2 3 4
P(X) 0.17 0.23 0.27 0.24 0.09
F(x) 0.17 0.04 0.65 0.91 1