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Dennis_Churaev [7]
3 years ago
15

Mr. McBride ordered 6 cheese pizzas and 7 pepperoni pizzas and paid $153.50 for his son's birthday party. He realized he was goi

ng to run out of pizza and made a second order. This time, he ordered 2 cheese and 2 pepperoni pizzas and paid $47.00. What is the cost of one pepperoni pizza?
Mathematics
1 answer:
Marat540 [252]3 years ago
8 0

Let x = cost of one cheese pizza.

Let y = cost of one pepperoni pizza.

Set up a system of equations.

6x + 7y = 153.50

2x + 2y = 47.00.

Multiply the second equation by -3

6x + 7y = 153.50

-6x - 6y = -141.00.

Add the equations together

y = $12.00.

Plug 12 into one of our original equations.

2x + 2(12) = 47.

Simplify the left side.

2x + 24 = 47.

Subtract 24 from each side.

2x = 23.

Divide each side by 2

x = $11.50

In conclusion, one pepperoni pizza costs $12.00

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Answer:

X, process, y

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X = -2, -1, 0, 1, 2,

Y = -6, -3, 0, -3, -6

Step-by-step explanation:

Coordinates for the graph: (-2,-6), (-1,-3), (0,0), (1,3), (2,6)

Graph is the image I added onto this.

Solving for Y below:

3(-2)= -6

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Hope this helps.

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3 years ago
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Ghella [55]
<h3>The given expression as single exponent is:</h3>

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<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

4^4 \times 4^{-7} \times 4

In exponents,

When the base is same, exponents can be added

Which means,

a^m \times a^n = a^{m+n}

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4^4 \times 4^{-7} \times 4 = 4^{4-7+1}\\\\Simplify\\\\4^4 \times 4^{-7} \times 4 = 4^{-3+1} \\\\4^4 \times 4^{-7} \times 4 = 4^{-2}

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Hello there!

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So the answer is x = 3.



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